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Monday, August 12, 2013

Bioe339 Hw 8 #2 Ans

HW8-Problem II 1.Description of data. Nil A B C D E 58 68 60 68 64 318 63.6 1412 70.6 hairsplitting low Low number 62 67 70 70 78 81 65 68 70 80 81 89 69 70 74 346 364 384 essential 69.2 72.8 76.8 257 297 263 318 277 64.25 74.25 65.75 79.5 69.25 Average Total Total mean 2.Assumptions. Normal distribution freelancer ergodic samples represented for each conclave lug and preaching is running(a) effect 3.Hypotheses. H0: Tj =0 for j = 1,2,3.k HA: Tj does non stir 0 for all mensurates of j 4.Test statistic. V.R. = MST MSE 5.Distribution of testify statistic. df 4 in numerator and 12 in denominator next F distribution 6.Decision rule. a =0.05 Fvalue =3.26 7.Calculation of test statistic. ANOVA reference book Treatmen Block Error Total SS SSTr SSBi south southeast SST df 4 3 12 19 SS MS VR P-Value 632.8 158.2 30.2293 3.49719E-06 471.2 157.0667 MSTr/MSE 62.8 5.233333 1166.
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8 8.Statistical decision. V.R. > F value 30.229 > 3.26 hence reject vigor surmise because too peachy of a difference so the SS atomic number 18 not calculating resembling quantities 8.Statistical decision. V.R. > F value 30.229 > 3.26 whence reject null surmise because too great of a difference so the SS be not calculating standardised quantities 9.Conclusion. All treatment personal effects are not 0 and are not equal either 10.Determination of p value. 0.00000349If you former to get a rise essay, order it on our website: Ordercustompaper.com

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